0 votes 0 votes Mohitkumaraiactr asked Nov 19, 2017 Mohitkumaraiactr 543 views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Shubhanshu commented Nov 19, 2017 reply Follow Share 1/12 ?? 0 votes 0 votes Mohitkumaraiactr commented Nov 19, 2017 reply Follow Share don't know , i was getting 3 / 12 could you please explain 0 votes 0 votes Shubhanshu commented Nov 19, 2017 reply Follow Share There are three cases AA, AB AND AD, these are favourable cases according to the question. 1/3( 3/12 × 3/12 + 3/12×5/12 + 3/12×4/12) 1/3 × 36/144 12/ 144 1/12. 0 votes 0 votes abhishek tiwary commented Nov 19, 2017 reply Follow Share what is the answer i am getting 4/12 0 votes 0 votes Mohitkumaraiactr commented Nov 19, 2017 reply Follow Share i don't have its answer. 0 votes 0 votes Shubhanshu commented Nov 19, 2017 reply Follow Share May you explain your steps. 0 votes 0 votes Surajit commented Nov 19, 2017 reply Follow Share Not sure if I understood the question properly, what does it mean by 'the student'??Is it the same as the student of section C or it can be any random student and his friend?Assuming 'the student' referes student from section C. No of people with no classes in section A,B,D are 1/3*3 = 1,1/3*5 = 5/3 ,1/3*4 =4/3. Now if I pick randomly I can select any one A B or D section,P(no classes).So 1/3 * (1+5/3+4/3) = 12/9 No of people in section A who does not have any classes,P(A)= 1/3*3 = 1 P(friend from section A|friend does not have classs) = P(A|no classes) = 1/(12/9) = 3/4 .(answer). 0 votes 0 votes abhishek tiwary commented Nov 19, 2017 reply Follow Share choosing the friend from class A,B,D=1/3,1/5,1/4 choosing the friend from total friend which are from class A,B,D=1/4,5/12,1/3 probability of no classes in each section=1/3 prob of friend is from class A=(1/3*1/4)/1/3*1/4+1/3*5/12+1/3*1/3=12/36 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes I think 3/12 is the answer. gatenidhi2018 answered Oct 21, 2018 gatenidhi2018 comment Share Follow See 1 comment See all 1 1 comment reply deepanshu sharma 3 commented Oct 22, 2018 reply Follow Share please explain 0 votes 0 votes Please log in or register to add a comment.