4 votes

The values of P,Q,R, if 47Q80 is the 10's c complement of RPRP0 are

a)4, 3, 2 b) 5,4,4 c)3,4,5 d)2,4,5

a)4, 3, 2 b) 5,4,4 c)3,4,5 d)2,4,5

2 votes

Best answer

**Ans is option D.**

10's compliment of base 10 number X with n digits = 10^{n} - X

here, n = 5, X = RPRP0

hence

100000 - RPRP0 = 47Q80

from unit place : 0-0 = 0

then, 10 - P = 8. Hence P =2.

then, 9 - R = Q ( compute this later) ...(1)

then 9 - P = 7. Confirmation of P =2.

then, 9 - R = 4. hence R =5.

again from eq (1), 9-R = Q => 9-5 = 4, hence Q =4.

**P = 2, Q=4, R =5**