doubt in combination anyone who can explain it :) closed

Question

let  2 different objects  are to be distributed among 2 persons   { no restriction on number of distribution of object but all  objects should be distributed }  

 

sol .   i got  answer = 4   , by using formula     r^n    , where r = no. of person  and n = no. of object

 

but   possible cases can be  p1(he can get 2 object)  , p2(he can get 0)

                                              p1(he can get 1 object) , p2(he too can get 1 object)

                                              p1(he can get 0 object) , p2(he can get 2 object)   

what could be the 4th case  ???  

4 case could not be   p1(he got 0 object) , p2(he got  0  object)   because all objects should be distributed

 

help me where iam wrong ?

Comments

since objects are distinct say o1 and o2, one case where first person gets o1 and second person gets o2 and opposite in second case. right?

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 Rishabh Jain 1  @yes i   was counting the total no. agreed thankyou =D

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let 2 objects be 0 and 1 respectivily and 2 person A and B,

A	B
0	1
1	0
01
	01

 

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@joshi_nitish got it bro actuallly i was counting total no. thats why thanks