2 votes 2 votes Digital Logic digital-logic min-no-gates made-easy-test-series + – Ismail asked Jan 27, 2018 • edited Mar 4, 2019 by ajaysoni1924 Ismail 684 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply gauravkc commented Jan 27, 2018 reply Follow Share Getting equation is easy. If someone has trick to get number of gates from eqn please share :p 1 votes 1 votes Anand. commented Jun 12, 2018 reply Follow Share Equation is $y = A'B' + A'C' + B'C'=C'(A'+B')+A'B'$ is answer $4$? 0 votes 0 votes BASANT KUMAR commented Jun 12, 2018 i edited by BASANT KUMAR Jun 13, 2018 reply Follow Share If we take pos of this equation then answer is 4 but if we take sop then answer is 5 .which one is correct?? 0 votes 0 votes pranay91331 commented May 11, 2019 reply Follow Share What is the answer. iam getting 6? 1 votes 1 votes Please log in or register to add a comment.
1 votes 1 votes 6 NOR Gates are required. Antaroop answered Jan 14, 2020 Antaroop comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes F(A,B,C)=(B'+C')*(A'+C')*(A'+B') is s.o.p of given equation so total number of nor gate is 5 BASANT KUMAR answered Jun 12, 2018 BASANT KUMAR comment Share Follow See all 0 reply Please log in or register to add a comment.
