8 8 votes Hi Guys, Any justification for the mentioned answer or what could be the answer ? Digital Logic digital-logic prime-implicants k-map + – Chhotu 6.0k views answer comment Share Follow Print See all 4 Comments 4 4 Comments reply nikhil gate 2018 commented Aug 7, 2018 reply Follow flag C is correct because in cyclic k map every minterm cover by 2 pi so c is correct 0 0 replyShare Verma Ashish commented Aug 30, 2018 i edited by Hira Thakur Jul 19, 2023 reply Follow flag See the answer of this question https://gateoverflow.in/173362/self-doubt 0 0 replyShare manisha11 commented Sep 13, 2020 reply Follow flag Here, in cyclic function: There are no EPI Every minterm is covered by atleast 2 PI. All minterms are of same size. For minimal form, when you try to take PI, we make sure that we use minimum PI, when there exists more than 1 minimal form, due to the above conditions, when you choose different minterms for other form, it ends up that they don’t have common PI, I would suggest to try that via Kmap to get more clarity. 0 0 replyShare tirth_patel commented Sep 7, 2021 reply Follow flag https://www.geeksforgeeks.org/prime-implicant-chart-for-minimizing-cyclic-boolean-functions/ 0 0 replyShare Please log in or register to add a comment.
