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Question

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ans C)??

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Yeah its C).

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I am not getting the meaning of last time - "What is the probability that each passenger get down at each stage.?"
Please explain me.

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Plz explain it ?

Answer 1

if each passenger gets down at 3 different stops,then total number of possible cases is = 3!=6

and each case has a probability of $\frac{1}{3}$*$\frac{1}{3}$*$\frac{1}{3}$=$\frac{1}{27}$ (Because given that they independently taking the decision)

so total probability = 6 * $\frac{1}{27}$=$\frac{2}{9}$

Answer 2

since there are 3 passenger and 3 stops. Let passenger be A,B,C and stops be X,Y,Z. Each passenger can has 3 choice to get down at stop. so number of way in which passenger get down from auto is 3*3*3. now we have to find probabilty for each passenger get down at each stop. Passenger A can get down at any stop X,Y,Z. say he get down at X. Now passenger B has choice of Y,Z. similary Passenger C left with only one choice. so total choice 3*2*1.

probability=3*2*1/27=2/9