0 0 votes For any three sets $P$,$Q$ and $R$, $s$ is an element of $(P \bigtriangleup Q)\bigtriangleup R$ if $s$ is in Exactly one of $P$,$Q$ and $R$ at least one of $P,Q,R$ but not in all three of them at the same time exactly two of $P,Q$ and $R$ exactly one of $P,Q$ and $R$ or in all the tree of them. Set Theory & Algebra set-theory&algebra + – Sandy Sharma 2.0k views answer comment Share Follow Print See all 5 Comments 5 5 Comments reply Show 2 previous comments Kushagra Chatterjee commented Apr 28, 2018 reply Follow flag Oh yes i missed that option D will be the correct answer. 0 0 replyShare Sandy Sharma commented Apr 28, 2018 reply Follow flag Pls explain how? 0 0 replyShare Kushagra Chatterjee commented Apr 28, 2018 reply Follow flag Let A = (PΔQ)ΔR Check it when s belongs to exactly one of P,Q and R does s belongs to A Then check when s belongs to exactly two of P,Q and R does s belongs to A. Then checj when s belongs to all three of them does s belongs to A You will get your answer 0 0 replyShare Please log in or register to add a comment.
1 1 vote Is it correct? Kajal K answered Apr 28, 2018 Kajal K comment Share Follow See all 3 Comments 3 3 Comments reply Sandy Sharma commented Apr 28, 2018 reply Follow flag Thanks. i understood the left part but what did you do in the right part taking three S as P,Q and S? 0 0 replyShare Kajal K commented Apr 28, 2018 reply Follow flag In the right part,I took the element S in all three sets namely P,Q and R and then solved.You may solve like this too both are correct 0 0 replyShare Sandy Sharma commented Apr 28, 2018 reply Follow flag Thanks. 0 0 replyShare Please log in or register to add a comment.