Answer C option
Function f2 = A'B+AB'+ AC'D
F2 = SOP ( 4,5,6,7,8,9,10,11,13)
then Function F1 should be SOP (4,5,8,10)
|
A'B' |
A'B |
AB |
AB' |
C'D' |
|
1 |
|
1 |
C'D |
|
1 |
1 |
1 |
CD |
|
1 |
|
1 |
CD' |
|
1 |
|
1 |
Option C
F3 :∏(1,12,14,15) * d(4,5,8,10) compliment is F3: ∏(0,2,3,6,7,9,11,13)* d(4,5,8,10) it represents POS
then SOP will F3 can be represent in this form ∑(1,12,14,15) + d(4,5,8,10)
|
A'B' |
A'B |
AB |
AB' |
C'D' |
|
d |
1 |
d |
C'D |
1 |
d |
|
|
CD |
|
|
1 |
|
CD' |
|
|
1 |
d |
(F1 AND F2) OR F3' = ∑(1,4,5,8,10,12,14,15)
(((4,5,8,10) ⋂ ( 4,5,6,7,8,9,10,11,13)) ⋃ (1,12,14,15)+d(4,5,8,10))
= (1,4,5,8,10,12,14,15).