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I think all options are wrong.

in Digital Logic by Active (4.7k points)
edited by | 117 views
0
I thinks D
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I tried so many times, not getting D as answer
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I tried by option elimination and left with D, is the answer right
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Try doing using expressions and share the result.
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Plug values

T = 0

P = 0

R = 1

S = 1

You'll not get 1 as output

so D is incorrect
+1
i'm getting $G = T' (P + R'S')$
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Exactly @Utkarsh
+1

yes, i too get what Mk Utkarsh get

 

I tried by option elimination and left with D, is the answer right

if it is a standard exam, then it helps, unfortunately the test series or not standard.

Check the option C, they have variable Q, but in the diagram, variable Q is not present

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nice observation
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@Shaik Masthan @Mk Utkarsh sir

What is the easiest approach to solve such type of questions?

Plug values 

T = 0

P = 0

R = 1

S = 1

You'll not get 1 as output 
 

if R =1 and S=1 then R EXOR S is zero....how to say T as the answer? 

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@himgta all the options are wrong. final answer would be G=T′(P+R′S′)

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What is the easiest approach to solve such type of questions?

normal procedure always takes less time on this type of questions and yields the correct answer..

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all option is incorrect .correct output will be T only.

1 Answer

+2 votes

CHECK WHERE YOU DONE MISTAKE

by Junior (691 points)
0
Yup..I got the same
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