1 1 vote The value of $\int_c \frac{2x^2-5}{(x+2)^2 (x^2+4)x^2}dx$, (where $c$ is the square with vertices $1+i, 2+i, 2+2i, i+2i$) is: $0$ $\pi i$ $2 \pi i$ $4 \pi i$ Others nielit-2018 non-gatecse integration + – Arjun 924 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.