0 votes 0 votes Shadan Karim asked Jan 5, 2019 Shadan Karim 228 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Magma commented Jan 5, 2019 reply Follow Share -9 0 votes 0 votes Shadan Karim commented Jan 5, 2019 reply Follow Share Given is 3 0 votes 0 votes Shubhgupta commented Jan 5, 2019 reply Follow Share given that g(x)=$1-x+x^{2}$ and f(x)=$ax+b$ then (gof)(x)= g(ax+b) = $1-ax-b+a^{2}x^{2}+b^{2}+2abx= 9x^{2}-9x+3$ $a^{2}x^{2}+(2ab-a)x+(b^{2}-b+1)=9x^{2}-9x+3$ Then $a=\pm 3 $ and $b=2,-1$ 2 votes 2 votes Please log in or register to add a comment.
0 votes 0 votes $(gof)(x) = g(f(x)) = g(ax+b) $ $= 1 - ax -b + (ax+b)^2 $ $= 1 - ax -b + (ax)^2 + b^2 + 2$ $a^2x^2+(2ab−a)x+(b2−b+1)=9x^2−9x+3$ Then $a=±3$ and $b=2,−1$ gmrishikumar answered Jan 5, 2019 gmrishikumar comment Share Follow See all 0 reply Please log in or register to add a comment.