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The Number of Labelled possible graph given below ?


what I did was →

we doesn’t  remove any of the edge out of 4   = $\binom{4}{0}$   [Because a Graph is sub-graph of itself]

we can remove any of one edge out of 4 = $\binom{4}{1}$

we can remove any of the two edges out of 4  = $\binom{4}{2}$

similarly ,  $\binom{4}{3}$ , $\binom{4}{4 }$

then  , add of the them


in Graph Theory by Boss (13.9k points)
edited by | 114 views

[Because a Graph is sub-graph of itself]

A subgraph G^' of a graph G is a graph G^' whose vertex set and edge set are subsets of those of G.

if u are playing with edges then u can also play with vertices. like graph can contain only 1 vertex. ( 4 cases)

or may be combination of vertices and edges like 2 vertex 1 edge etc.


thanks @Satbir

What's the final solution then?
We can also look at this question as finding number of possible subsets of a set.

Let S be a set with all the 4 edges, number of subgraphs possible is the number of subsets of S, so answer should be 16.

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