0 0 votes Can a countable infinite lattice be bounded? Set Theory & Algebra lattice + – Manoj Kumar Pandey 1.3k views answer comment Share Follow Print See all 6 Comments 6 6 Comments reply Show 3 previous comments Hradesh patel commented Dec 28, 2019 reply Follow flag @smsubham. Above link...have two answer...both answer contradictory... = {2^(-k) / k is +ve interger} It's bounded and countable infinite....but it's latiice how??? 0 0 replyShare `JEET commented Dec 28, 2019 reply Follow flag Yes. 0 0 replyShare usher commented Oct 25, 2024 reply Follow flag every finite lattice is a bounded lattice. anything which has no upper bound or no lower bound is infinite, so not a bounded lattice. 0 0 replyShare Please log in or register to add a comment.
0 0 votes Z with added endpoints. it is countable infinite latice are bounded Parmar_Meet27 answered Nov 22, 2025 Parmar_Meet27 comment Share Follow 0 reply Please log in or register to add a comment.