0 votes 0 votes Assume memory access time is 10 μs and reading a page from disk takes 10 ms. If page fault occur in 0.5% of the memory references then what is the average memory access time (in μsec)? Operating System operating-system + – prathams asked Dec 20, 2015 prathams 428 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply pritika kundu commented Dec 20, 2015 reply Follow Share 5010microsec? 0 votes 0 votes prathams commented Dec 20, 2015 reply Follow Share not sure, i am getting 59.95 μsec. But answer given is 10 μsec. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Main memory access time (m) = 10 microsec Service time (ps) = 10 milisec Page fault rate (p)= 0.5% = 5*10^3 Thus EMAT= m+p(ps) = 10 microsec + 5*10-3*10*10^-3 = 10 microsec + 5 * 10^-6 = 10 microsec + 5 microsec = 15 microsec Saraswati Walujkar answered Dec 20, 2015 Saraswati Walujkar comment Share Follow See all 0 reply Please log in or register to add a comment.