TAG will take= 9 bits
SET will need 4 bits and
WORD will need 7 bits of the cache memory location
(using the above conclusion as derived in previous question)
The memory location 0C795H can be written as 0000 1100 0111 1001 0101
Thus TAG= 9 bits = 0000 1100 0
SET =4 bits =111 1
WORD = 7 bits =001 0101
Therefore, the matching option is option A.