RAW hazard

Question

Comments

It is just made easy myth...that raw dependency can only counted in adjacent  instructions and also they have given all the answer key according to that but it not true

Answer 1

(1,2)

(1,3)

(2,3)

(2,4)

(3,4)

so as per me too 5

Comments

MADE EASY TEACHER once said that RAW occurs between two consecutive instruction that is (1,2) is RAW but (1,3) is not

But i have not read anything like this anywhere.. so i think 5 is correct also...

btw as per their suggession it is 3

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Yes...answer would 5..

I agree with Uddipto.

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PLEASE provide good source to read about RAW, WAR, and WAW.

Answer 2

Ans will be 3.

(2-1), (3-2) and (4-3).

In RAW, we observe if any in-register is equal to any next consecutive out-register. If yes, then it is RAW.

In-register and out register is explained as

Add ro=r1,r2

Sub r5=r2,r3

In-register    out-register

r1,r2,r3.            ro,r5

And yes it is NOT RAW.

Tips: we compare in register with out register, but not vice-versa.