Applied Test Series

Question

Consider a disk with a sector size of 512 bytes, 1000 tracks per surface, 25 sectors per track, 5 double-sided platters, and average seek time of 10 msec. The capacity of tracks in bytes is _____ KB

Comments

here question telling about  capacity of tracks = number of sector per track  * sector size =12.5 KB

Answer 1

Given,

Sector size – 512 bytes

Number of double-sided disk platters - 5

Number of tracks per each side of each disk platter – 1000

Number of sectors per track – 25

Average seek time – 10 msec

 

The capacity of track can be calculated as follows;

 

Capacity of track = bytes/track = bytes/sector * sectors/track

                = 512 bytes/sector * 25 sectors/track = 12800 bytes

                = 12800/1024 KB = 12.5 KB