5 5 votes In TCP, MSS is 8B. If during the 6th RTT the network is congested and timeout occurs, by using the congestion algorithm, then the threshold value is _________(in Bytes). (assume initial congestion window size for the first transmission is 1 MSS) Computer Networks test-series computer-networks congestion-control transport-layer + – LRU 2.6k views answer comment Share Follow Print See all 10 Comments 10 10 Comments reply Yaman Sahu commented Dec 11, 2021 reply Follow flag Ans is 256 Bytes? 2 2 replyShare Vishal_kumar98 commented Dec 11, 2021 reply Follow flag I guess it should be 128 Bytes 1 1 replyShare jugnu1337 commented Dec 12, 2021 reply Follow flag @Yaman Sahu how ? can u write sequence… 0 0 replyShare Yaman Sahu commented Dec 12, 2021 reply Follow flag 1,2,4,8,16,32,64(TO occurs) therefore, threshold = 64/2 = 32 MSS = 32 * 8= 256 Bytes 1 1 replyShare jugnu1337 commented Dec 12, 2021 reply Follow flag @Yaman Sahu they also given mss 8 where we use this? 0 0 replyShare Yaman Sahu commented Dec 12, 2021 reply Follow flag therefore, threshold = 64/2 = 32 MSS = 32 * 8= 256 Bytes to calculate in Bytes 1 1 replyShare Yaman Sahu commented Dec 12, 2021 reply Follow flag @LRU, @jugnu1337 Refer this question https://gateoverflow.in/1794/Gate-cse-2014-set-1-question-27 1 1 replyShare Vishal_kumar98 commented Dec 12, 2021 reply Follow flag How are you justifying the sentence "During the 6th RTT, Will you please elaborate? 1 1 replyShare Yaman Sahu commented Dec 12, 2021 reply Follow flag @Vishal_kumar98 Refer above question link first it explains in detail 1,2 means After 1RTT, cwnd = 2MSS (count ‘,’) 3 3 replyShare Sanjeev kumar Sen commented Jan 15, 2022 reply Follow flag @yaman sahu they have asked for time out at 6th not after 6th so your provided solution should have 16*8=128 1 1 replyShare Please log in or register to add a comment.
Best answer 2 2 votes 1st transmission: 1 MSS 2nd transmission: 2 MSS 3rd transmission: 4 MSS 4th transmission: 8 MSS 5th transmission: 16 MSS 6th transmission: 32 MSS [ Window th = 32 / 2 = 16 MSS] 16 MSS = 16 * 8 = 128 B Vishal_kumar98 answered Dec 13, 2021 • selected Dec 27, 2021 by LRU Vishal_kumar98 comment Share Follow See 1 comment 1 1 comment reply Aaru_2023 commented Jan 15, 2023 reply Follow flag @Vishal_kumar98 what will be the congestion threshold for slow start? 0 0 replyShare Please log in or register to add a comment.
1 1 vote 1MSS----(RTT)-->2MSS—(RTT)---->4MSS----(RTT)-->8MSS---(RTT)--->16MSS----(RTT)-->32MSS------>Timeout Final CWND = 32 Threshold value = 32/2 = 16 MSS = 16*8 bytes = 128 Bytes aaaakash001 answered Nov 14, 2022 aaaakash001 comment Share Follow 0 reply Please log in or register to add a comment.
