4 votes 4 votes In TCP, MSS is 8B. If during the 6th RTT the network is congested and timeout occurs, by using the congestion algorithm, then the threshold value is _________(in Bytes). (assume initial congestion window size for the first transmission is 1 MSS) Computer Networks test-series computer-networks congestion-control transport-layer + – LRU asked Dec 11, 2021 LRU 1.6k views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply Yaman Sahu commented Dec 11, 2021 reply Follow Share Ans is 256 Bytes? 2 votes 2 votes Vishal_kumar98 commented Dec 11, 2021 reply Follow Share I guess it should be 128 Bytes 1 votes 1 votes jugnu1337 commented Dec 12, 2021 reply Follow Share @Yaman Sahu how ? can u write sequence… 0 votes 0 votes Yaman Sahu commented Dec 12, 2021 reply Follow Share 1,2,4,8,16,32,64(TO occurs) therefore, threshold = 64/2 = 32 MSS = 32 * 8= 256 Bytes 1 votes 1 votes jugnu1337 commented Dec 12, 2021 reply Follow Share @Yaman Sahu they also given mss 8 where we use this? 0 votes 0 votes Yaman Sahu commented Dec 12, 2021 reply Follow Share therefore, threshold = 64/2 = 32 MSS = 32 * 8= 256 Bytes to calculate in Bytes 1 votes 1 votes Yaman Sahu commented Dec 12, 2021 reply Follow Share @LRU, @jugnu1337 Refer this question https://gateoverflow.in/1794/Gate-cse-2014-set-1-question-27 1 votes 1 votes Vishal_kumar98 commented Dec 12, 2021 reply Follow Share How are you justifying the sentence "During the 6th RTT, Will you please elaborate? 1 votes 1 votes Yaman Sahu commented Dec 12, 2021 reply Follow Share @Vishal_kumar98 Refer above question link first it explains in detail 1,2 means After 1RTT, cwnd = 2MSS (count ‘,’) 3 votes 3 votes Sanjeev kumar Sen commented Jan 15, 2022 reply Follow Share @yaman sahu they have asked for time out at 6th not after 6th so your provided solution should have 16*8=128 1 votes 1 votes Please log in or register to add a comment.
Best answer 2 votes 2 votes 1st transmission: 1 MSS 2nd transmission: 2 MSS 3rd transmission: 4 MSS 4th transmission: 8 MSS 5th transmission: 16 MSS 6th transmission: 32 MSS [ Window th = 32 / 2 = 16 MSS] 16 MSS = 16 * 8 = 128 B Vishal_kumar98 answered Dec 13, 2021 • selected Dec 27, 2021 by LRU Vishal_kumar98 comment Share Follow See 1 comment See all 1 1 comment reply Aaru_2023 commented Jan 15, 2023 reply Follow Share @Vishal_kumar98 what will be the congestion threshold for slow start? 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes 1MSS----(RTT)-->2MSS—(RTT)---->4MSS----(RTT)-->8MSS---(RTT)--->16MSS----(RTT)-->32MSS------>Timeout Final CWND = 32 Threshold value = 32/2 = 16 MSS = 16*8 bytes = 128 Bytes aaaakash001 answered Nov 14, 2022 aaaakash001 comment Share Follow See all 0 reply Please log in or register to add a comment.