edited by
431 views
0 votes
0 votes

edited by

1 Answer

0 votes
0 votes

 S2 select line is output OR gate .So  C+1=1   , C+0 = C  whatever value of C will be output will be 1. So  S2 will always be 1.

In the above MUX     : X0,X3,X5,X6 are active high .

By using characteristic equation of MUX - 

 Y = E' ( S2'S1'S0' X0 + S2'S1S0 X3 + S2S1'S0 X5 + S2S1S0' X6 )  I have not included rest all becoz they are active low .

In the above equation  E =0 and S2 will always be 1. so X0 and X3 terms become 0 , X5=1,X6=1

So the final output will be ->

Y = S1'S0 + S1S0' => A'B + AB'    i.e   A XOR B.

Related questions

0 votes
0 votes
0 answers
2
Rohit Chakraborty asked Oct 9, 2023
324 views
Can you explain the diagram given in the question along with the solution?
0 votes
0 votes
1 answer
3
3 votes
3 votes
1 answer
4