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aptitude-race

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Distance $ = 100$m

Time taken by $A$ to complete $100$m $= t$sec

Time taken by $B$ to complete $100$m $=(t+6)$sec

Time taken by $C$ to complete $100$m $=(t+6)+3=(t+9)$sec

So $A$ beat $C$ by $9$ sec and by $25$m

it means $C$ takes $9$ sec to cover $25$m

Speed of $C$ $=\frac{25}{9}$ m/s

Time taken by $C$ $= \frac{100}{\frac{25}{9}} = 36$ sec

$t+9 =36$ sec

Time take by $A$ to complete $100$m, $t=27$ sec
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