3 votes 3 votes Which one of the following options is CORRECT for the given logic circuit? $P=1, Q=1 ; X=0$ $P=1, Q=0 ; X=1$ $P=0, Q=1 ; X=0$ $P=0, Q=0 ; X=1$ Digital Logic goclasses2024-mockgate-11 goclasses digital-logic combinational-circuit digital-circuits multiple-selects 1-mark + – GO Classes asked Jan 13 • retagged Jan 13 by Lakshman Bhaiya GO Classes 406 views answer comment Share Follow See 1 comment See all 1 1 comment reply GO Classes Support commented Jan 16 reply Follow Share $ \large{\colorbox{yellow}{Detailed video solution of this question with direct time stamp}}$ All India Mock Test 2 - Solutions Part 3 0 votes 0 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes The output expression can be written as:$X=\bar P+PQ \implies X=(\bar P+P).(\bar P+Q)$ which is equivalent to $X=\bar P+Q$ Now only option $(D)$ satisfy this equation as $X=\bar 0+0=1$ Hira Thakur answered Jan 14 • selected Jan 15 by Deepak Poonia Hira Thakur comment Share Follow See all 0 reply Please log in or register to add a comment.
