1 1 vote The Newton-Raphson iteration $x_{n+1} = \frac{1}{2}\left(x_n+\frac{R}{x_n}\right)$ can be used to compute the square of R reciprocal of R square root of R logarithm of R Numerical Methods gatecse-2008 newton-raphson normal numerical-methods out-of-gatecse-syllabus + – Kathleen 6.5k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply akash.dinkar12 commented Aug 6, 2018 reply Follow flag See this... 0 0 replyShare P0535_Yedidyah_Sagar commented Aug 8, 2025 reply Follow flag Out of syllabus :) 2 2 replyShare Please log in or register to add a comment.
Best answer 3 3 votes The given expression can be rewritten as, xn+1 = xn - (xn2 -R)/2xn therefore, it computes the square root R. answer (C) is correct. suraj answered Sep 12, 2014 • selected Jul 25, 2015 by Arjun suraj comment Share Follow 0 reply Please log in or register to add a comment.