5 votes 5 votes Let $A, B$ be two sets. Let $\bar{A}$ denote the complement of set $A$ (with respect to some fixed universe), and $( A - B)$ denote the set of elements in $A$ which are not in $B$. Set $(A - (A - B))$ is equal to: $B$ $A\cap \bar{B}$ $A - B$ $A\cap B$ Set Theory & Algebra goclasses2025_cs_wq4 goclasses set-theory&algebra set-theory 1-mark + – GO Classes asked Apr 3 GO Classes 226 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
6 votes 6 votes Detailed Video Solution with timestamp: https://youtu.be/mOfUwNN2JP8?si=_drDwATDEUxF7CKR&t=2128 Source: https://gateoverflow.in/18394/tifr-cse-2010-part-a-question-15 $(A - (A - B)) = A \cap (A \cap B')'$ Since $A - B = A \cap B'$ $= A \cap (A' \cup B)$ Since $(A \cap B)' = A' \cup B'$ $= A \cap B$ Option $D$ GO Classes answered Apr 3 • edited Apr 4 by GO Classes Support GO Classes comment Share Follow See all 0 reply Please log in or register to add a comment.
