Simplification and Complement of Boolean expressions.

Question

a). Simplify the following Boolean expressions.
i. A’C’ + ABC + AC’ to three literals
ii. (x’y’ + z)’ + z + xy + wz to three literals .
iii. A’B(D’ + C’D) + B(A +A’CD) to one literal
iv. (A’ + C)(A’ + C’)(A + B + C’D) to four literals

b. Obtain the complement of the following Boolean expressions.
i. B’C’D + (B + C + D)’ + B ’C’D’E
ii. AB + (AC)’ + (AB + C)
iii. A’B’C’ + A'BC’ + AB’C’ + ABC’
iv. AB + (AC)’ + AB’C

Comments

Use K-map approach for simplification of expressions and for finding complement, make kmap and entries for POS to get complement of SOP expressions

Answer 1