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3 Answers

0 0 votes

Short trick..!!

If 2 variables have the same effect on the function...!!
Then consider them equal to each other, to find the maximum of the output..!!

So, Let x=y..
2*(x^2) = 2..
So, x62 = 1..
So, x = +1 / -1 = y...!!

So, the maximum of x*y = 1...!!

0 0 votes
The Questiion is
MAX xy

subject to x^2+y^2 = 2
Now The Lagrangian L(X,λ) = xy + λ(x^2+y^2-2)
Now Differentiate wrt x we will get λ = -(y/2x) and
wrt y we will get λ = -(x/2y)
Equating both as same we will get x = y = +1 , -1
Now the max value will be 1
Position:
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