The Questiion is
MAX xy
subject to x^2+y^2 = 2
Now The Lagrangian L(X,λ) = xy + λ(x^2+y^2-2)
Now Differentiate wrt x we will get λ = -(y/2x) and
wrt y we will get λ = -(x/2y)
Equating both as same we will get x = y = +1 , -1
Now the max value will be 1