0 votes 0 votes With 64 bit virtual addresses, a 4KB page and 256 MB of RAM, an inverted page table requires: 8192 entries 16384 entries 32768 entries 65536 entries Sanjay Sharma asked Jun 15, 2016 Sanjay Sharma 11.5k views answer comment Share Follow See 1 comment See all 1 1 comment reply S Ram commented Jan 4, 2019 reply Follow Share @Sanjay Sharma Sir in case we have not given PTE size for inverted page table what can be assumed?? 0 votes 0 votes Please log in or register to add a comment.
Best answer 5 votes 5 votes d) answer is 65536 size of ram / page size = inverted page table entries Inverted page tables have 1 entry / physical frame of memory Kapil answered Jun 15, 2016 • selected Jun 15, 2016 by Sanjay Sharma Kapil comment Share Follow See all 0 reply Please log in or register to add a comment.