The boolean expression $AB+AB'+A'C+AC$ is independent of the boolean variable
We have AB+AB'+A'C+AC
We can rewrite above equation as
AB(C+C')+AB'(C+C')+A'(B+B')C+A(B+B')C ....(As (C+C')=0, (B+B')=0)
Eliminating Common Terms and rewrite equation as.
expression in terms of minterms is
K-Map will be
Thus we can write Reduced equation as