2.2k views

Let $R_1$ and $R_2$ be regular sets defined over the alphabet, then

1. $R_1 \cap R_2$ is not regular
2. $R_1 \cup R_2$ is not regular
3. $\Sigma^* - R_1$ is regular
4. $R_1^*$ is not regular

retagged | 2.2k views

option C is correct

Regular sets are closed under union, intersection, complement, and kleen closure

But regular sets are not closed under infinite union
by Active (3.5k points)
selected by
+1 vote

"Regular languages are closed under Intersection, Union ,Kleens Closure ,Compliment"

According to this point option C is perfect

by Boss (42.4k points)
0
Sir  can you give example where
$\sum* - R1$ is not regular
0
∑∗−R1 is regular, this statement is true, not false.
0
Oh soory Sir, i didn't read the options carefully
0
ok sir