• edited by
285 views
2 2 votes
Let $m$ and $n$ be the numbers of points at which $f(x) = \max\{x, x^3, x^5, \dots, x^{21}\}$ for $x \in \mathbb{R}$ is not differentiable and not continuous, respectively. What is the value of $m + n$?

1 Answer

1 1 vote
For x =

 -infinity to -1 ,   f(x) = x     ( as it is the greatest in this range , other have more power so bigger negative value)

        -1. to 0 ,  f(x) = x^21.

          0 to 1  , f(x) = x

and 1 to  infinity  f(x) = x^21

So, given function is continuous every whare and is not differentiable at -1, 1, 0.

so m=3 and n=0 .

Hence m+n = 3
Position:
Show:

Related questions

2 2 votes
1 1 answer
1.4k
1.4k views
Kuldeep Pal asked Jan 6, 2018
1,385 views
At the point x = 1, the function
3 3 votes
2 2 answers
1.6k
1.6k views
Shubhanshu asked Dec 31, 2017
1,629 views
1) Consider f(x) = $|x|^{3/2}$ Check for Differentiability and Continuity. I am getting Cont and Differentiable both.2) Consider f(x) = $|x-1|^{3/2}$ Check for Differen...
1 1 vote
1 1 answer
255
255 views
Shubham Sharma 2 asked Jun 20, 2025
255 views
Let $f: \mathbb{R} \rightarrow \mathbb{R}$ be a function which is twice differentiable everywhere and suppose that $f^{\prime}(q)=0$ for every rational number $q.$ Find t...
0 0 votes
0 0 answers
248
248 views
Shubham Sharma 2 asked Jun 12, 2025
248 views
Let $f: \mathbb{R} \rightarrow(0, \infty)$ be a function satisfying $f(x+y)=f(x) f(y)$ for all $x, y \in \mathbb{R}$.Prove that if $f$ is continuous at 0 , then $f$ is co...