3 3 votes Consider the following statements about interrupts.$\text{S1}:$ A non vectored interrupt generally requires more time to identify the interrupting device compared to a vectored interrupt.$\text{S2}:$ In daisy chaining, the CPU polls every I/O device to determine which device requested the interrupt. Which of the following options is correct?$\text{S1}$ is TRUE and $\text{S2}$ is TRUE $\text{S1}$ is TRUE and $\text{S2}$ is FALSE $\text{S1}$ is FALSE and $\text{S2}$ is TRUE $\text{S1}$ is FALSE and $\text{S2}$ is FALSE CO & Architecture goclasses gate2026_cs_set2_memorybased co-and-architecture one-mark + – GO Classes 596 views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply GO Classes commented Feb 19 reply Follow flag Watch Detailed Video Solution Here! 0 0 replyShare Kush_Bhatt commented Feb 19 reply Follow flag @GO Classes, need to correct and B as well in PDF. 0 0 replyShare Please log in or register to add a comment.
0 0 votes statement1:Because the CPU must manually check multiple devices in non-vectored systems, it takes significantly more time than the direct "vectored" approach.(True) statement 2:When the CPU receives an interrupt request, it sends out an Interrupt Acknowledge (INTA) signal. This signal passes through the first device, then the second, and so on. The first device in the chain that actually requested the interrupt "intercepts" the signal and stops it from moving further down the chain.Polling is a software method where the CPU initiates the check. In Daisy Chaining, the CPU does not poll; the hardware signal automatically identifies the highest-priority device. so (False)so option B akash_kumar 9 answered Feb 13 • edited Feb 15 by akash_kumar 9 akash_kumar 9 comment Share Follow See all 2 Comments 2 2 Comments reply Sanjog karan commented Feb 14 reply Follow flag ig u did the typo option B is right u wrote A by mistake 1 1 replyShare akash_kumar 9 commented Feb 15 reply Follow flag Now i have corrected it. 1 1 replyShare Please log in or register to add a comment.