13 13 votes Which of the following is not valid Boolean algebra rule? $\text{X.X = X}$ $\text{(X+Y).X = X}$ $\overline{X}+\text{XY = Y}$ $\text{(X+Y).(X+Z) = X + YZ}$ Digital Logic digital-logic boolean-algebra isro2014 + – Isha Gupta 5.3k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply vijaycs commented Jun 23, 2016 reply Follow flag C. 0 0 replyShare Deepak Poonia commented Jul 24, 2025 reply Follow flag Detailed Video Explanation: https://youtu.be/DbKnUyyzlZs?t=5344 0 0 replyShare Please log in or register to add a comment.
Best answer 10 10 votes Answer is C x' + xy = (x' + x)(x' + y) = x' + y Kapil answered Jun 23, 2016 • selected Aug 26, 2016 by Prashant. Kapil comment Share Follow 0 reply Please log in or register to add a comment.
4 4 votes ans is C x'+xy =(x'+x)(x'+y)=1.(x'+y)=x'+y which is not equal to y a)is true as X.X=X b)(X+Y).X=XX+XY=X+XY=X(1+Y)=X IS ALSO TRUE D)is true as xx+xz+yx+yz=x+xz+yx+yz=x(1+z+y)+yz=x+yz Sanjay Sharma answered Jun 23, 2016 • edited Dec 5, 2017 by Meenakshi Sharma Sanjay Sharma comment Share Follow 0 reply Please log in or register to add a comment.
2 2 votes $X.X = X $OPTION(A) TRUE $(X+Y)X = X+XY=X(1+Y)=X $OPTION (B) TRUE $(X’+XY) = (X’+X)(X’+Y) = X’+Y ≠ Y$ OPTION (C) FALSE $(X+Y)(X+Z) = XX+XZ+XY+YZ=X+XZ+XY+YZ=X(1+Z+Y) + YZ = X+YZ$ OPTION (D) TRUE so only false rule is c answer (c) Musa answered Aug 25, 2020 Musa comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote A.X.X=X is valid B.(X+Y)X=X is valid using truth table. C.X'+XY=Y is not valid using truth table D.(X+Y)(X+Z)=X+YZ is valid by absorption rule Pranabesh Ghosh 1 answered Jun 23, 2016 Pranabesh Ghosh 1 comment Share Follow 0 reply Please log in or register to add a comment.