5 5 votes $n$-th derivative of $x^n$ is $nx^{n-1}$ $n^n.n!$ $nx^n!$ $n!$ Calculus isro2011 calculus differentiation + – go_editor 3.0k views answer comment Share Follow Print See 1 comment 1 1 comment reply vijaycs commented Jun 23, 2016 reply Follow flag Ans - D. n! 0 0 replyShare Please log in or register to add a comment.
Best answer 10 10 votes f(x) = xⁿ f'(x) = n x(n-1) f''(x) = n(n-1) x(n-2) f'''(x) = n(n-1)(n-2) x(n-3) fⁿ(x) = n! x(n-n) , and since n-n = 0, x0 =1, so fⁿ(x) = n! Hence,Option(D)n! is the correct choice. LeenSharma answered Jun 23, 2016 • selected Jun 23, 2016 by srestha LeenSharma comment Share Follow 0 reply Please log in or register to add a comment.