3 3 votes In a 2 level memory, if the level 1 memory is 5 times faster than level 2 and its access time is 10ns less than avg access time.Let the level 1 memory access time is 20ns. (a.)0.7 (b.)0.75 (c.)0.86 (d.)0.96 CO & Architecture + – gshivam63 5.1k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 1 1 vote let level 1 access time t1 & level 2 t2... then t2 = 5 t1-----> eq(1) t1 = tavg - 10====>eq2 tavg = t1 + 10 t1 = 20 ns (given) from eq1 we get,,, t2 =100 ns from eq2 we get,,, tavg = 30ns now for simultaneous memory organization.. tavg = H t1 + (1-H) t2 30 = H *20 + (1-H) *100 H = .875 Tauhin Gangwar answered Jun 28, 2016 • selected Jun 28, 2016 by gshivam63 Tauhin Gangwar comment Share Follow See all 10 Comments 10 10 Comments reply Show 7 previous comments shraddha priya commented Jul 9, 2017 reply Follow flag It would be really helpful if you could tell where I went wrong instead of just down-voting the comment. Thanks in advance. 2 2 replyShare Tauhin Gangwar commented Jul 13, 2017 reply Follow flag Shraddha u r right. 0 0 replyShare Shubhanshu commented Aug 11, 2017 reply Follow flag So by default we have to rake simultaneos access and if the qurstuon contain hierarichal access then we have to consider hierarchical approach right? 0 0 replyShare Please log in or register to add a comment.
0 0 votes Answer C Mishika_Trivedi answered Jan 31, 2025 Mishika_Trivedi comment Share Follow 0 reply Please log in or register to add a comment.