4 4 votes Identify the operation which is commutative but not associative? OR NOR EX-OR NAND Digital Logic ugcnetcse-dec2012-paper2 digital-logic digital-circuits multiple-selects + – go_editor 11.8k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 13 13 votes B and D are answers A. OR: 0+1 = 1+0 =1 => Commutative (0+1)+1= 1+1 =1 0+(1+1)= 0+1 =1 => Associative B. NOR 0 NOR 1 = 1 NOR 0 =0 => Commutative (0 NOR 1) NOR 1 =0 NOR 1 = 0 0 NOR(1 NOR 1) =0 NOR 0 = 1 => Not associative C. XOR 0 XOR 1 = 1 XOR 0 = 1 => Commutative (0 XOR 1) XOR 1 =1 XOR 1 = 0 0 XOR(1 XOR 1) = 0 XOR 0 =0 => Associative D. NAND 0 NAND 1 = 1 NAND 0 =1 => Commutative (0 NAND 1)NAND 1 = 1 NAND 1 =0 0 NAND (1 NAND 1) = 0 NAND 0 = 1 => Not associative Every logic gate follows Commutative law AND,OR,Ex-OR,EX-NOR follows Associative law. NAND,NOR doesn`t follow Associative law. AND ,OR follows Distributive law.Ex-OR,EX-NOR,NAND,NOR doesn`t follow Distributive law. sh!va answered Jul 11, 2016 • selected Aug 19, 2016 by Sankaranarayanan P.N sh!va comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes commutative means A op B = B op A for all values of A and B. associative means (A op B) op C = A op (B op C) for all values of A , B, and C. the above rules are applied on OR, NOR, EX-OR, NAND operations. Then finally conclude that NOR and NAND both operations are commutative but not associative. jaz answered Jul 11, 2016 • edited Jul 12, 2016 by jaz jaz comment Share Follow See 1 comment 1 1 comment reply sh!va commented Jul 11, 2016 reply Follow flag NAND is not associative 1 1 replyShare Please log in or register to add a comment.