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The 2's compliment representation of (-539)base 10 in hexadecimal is __________?

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Best answer
3 3 votes
$-(539)_{10} = -(21B)_{16}=-(0010 0001 1011)_2$.

Now in 2's complement representation negative numbers are represented in their 2's complement form. So, we should do a complement here and add 1 which gives,

$(1101 1110 0101)_2 = (DE5)_{16}$
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0 0 votes
2's complement representation is a weighted Code representation.

To represent negative no. MSB position ( which must 1) weight is -ve rest are +ve so

-539=-1024+485

101 1110 0101

MSB weight -1024 rest made +485 so collectively they are -539

Now to represent in hexa it should be muliple of 4 bit so add extra 1 in MSB(sign extension it wont affect the Value it remain still -539)

So finally

1101 1110 0101

= (DE5)16
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