48 48 votes The determinant of the matrix $$\begin{bmatrix}2 &0 &0 &0 \\ 8& 1& 7& 2\\ 2& 0&2 &0 \\ 9&0 & 6 & 1 \end{bmatrix}$$ $4$ $0$ $15$ $20$ Linear Algebra gatecse-2000 linear-algebra easy determinant + – Kathleen 14.5k views answer comment Share Follow Print See all 7 Comments 7 7 Comments reply Show 4 previous comments goku4199 commented Oct 26, 2025 1 flag: ✌ Spam (raghu_46 “Explanation missing and spamming with large space”) reply Follow flag Ans 0 0 replyShare js__ commented Nov 11, 2025 reply Follow flag how long does this method work (of Best Answer) and when it doesn't ? 1 1 replyShare vxi lin commented Dec 10, 2025 reply Follow flag @jeetsdo you have the solution to your problem now? 0 0 replyShare Please log in or register to add a comment.
Best answer 63 63 votes $\text{Let }|A|=\begin{vmatrix}2 &0 &0 &0 \\ 8& 1& 7& 2\\ 2& 0&2 &0 \\ 9&0 & 6 & 1 \end{vmatrix}$ $\implies |A|=2\times\begin{vmatrix} 1& 7& 2\\ 0&2 &0 \\ 0 & 6 & 1 \end{vmatrix}$ $\implies |A|=2\times 1\times \begin{vmatrix} 2 &0 \\ 6 & 1 \end{vmatrix}$ $\implies |A|=2\times 1\times (2-0)$ $\implies |A|=2\times 1\times 2=4$ Answer$: A$ Rajarshi Sarkar answered Jun 25, 2015 • edited May 10, 2019 by Lakshman Bhaiya Rajarshi Sarkar comment Share Follow See all 5 Comments 5 5 Comments reply Show 2 previous comments meghna commented Sep 28, 2018 reply Follow flag @ Soumya29 the determinant you calculated as product of diagonal entries is after applying elimination method, right? 0 0 replyShare Soumya29 commented Oct 1, 2018 reply Follow flag @meghna.. No..I applied it directly and this is a general procedure. You can apply it to find the determinant of any matrix that has lots of 0's in it. Upper triangular one is a special case of this method only. You can check the reference link in my above for it. 0 0 replyShare Arun_Kumar 1 commented Oct 8, 2024 reply Follow flag reference link not working 1 1 replyShare Please log in or register to add a comment.
18 18 votes I reduced it to an upper triangular matrix. Pronomita Dey 1 answered Jan 21, 2018 Pronomita Dey 1 comment Share Follow See 1 comment 1 1 comment reply Likun swain commented Dec 25, 2018 reply Follow flag @Pronomita Dey 1 after reducing R4=R4-9/2R1 , in row 4th column 3rd there should be 6. you wrote 0??? 4 4 replyShare Please log in or register to add a comment.
5 5 votes 2*1*2*1 = 4 so option A is right Rishi yadav answered Oct 14, 2017 Rishi yadav comment Share Follow 0 reply Please log in or register to add a comment.
3 3 votes 2*1*2*1=4 break it into determinant of smaller pieces where you are doing it in such a way that you should have to do lesser number of operations Bhagirathi answered Sep 26, 2014 Bhagirathi comment Share Follow See 1 comment 1 1 comment reply Pranav Madhani commented Dec 12, 2017 reply Follow flag if we do nornally by cofactor method we get 20 as ans why that's not true? 0 0 replyShare Please log in or register to add a comment.
2 2 votes in this type of question ask what is determinant of 4x4 matrix then first check which row or column has maximum number of zero’s.then find co-factor of this row and it will answer. for example first i will take first row and first element co-factor=2*(2*1-0)=4. Bikki_gupta answered Mar 20, 2021 Bikki_gupta comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote Answer is 4 Rahul_kumar3 answered Nov 24, 2023 Rahul_kumar3 comment Share Follow 0 reply Please log in or register to add a comment.