4 4 votes In propositional logic, given $P$ and $P \rightarrow Q$, we can infer ________ $\sim Q$ $Q$ $P \wedge Q$ $\sim P \wedge Q$ Mathematical Logic ugcnetcse-dec2015-paper3 propositional-logic mathematical-logic + – go_editor 4.5k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 2 2 votes Answer: B,C Given premises: $P, P \rightarrow Q$ Valid Conclusion: $Q$ (By Modus Ponens rule of inference) Transitively another Valid Conclusion: $P \wedge Q$ (By Conjunction rule of inference) Deepak Poonia answered Dec 8, 2022 • selected Dec 8, 2022 by gatecse Deepak Poonia comment Share Follow 0 reply Please log in or register to add a comment.
3 3 votes P -> Q ans P infer to Q Using : Modus Ponens B is answer Prashant. answered Aug 11, 2016 Prashant. comment Share Follow 0 reply Please log in or register to add a comment.
2 2 votes P -> Q = ~P V Q So we can infer Q answer is B sh!va answered Aug 11, 2016 • edited Apr 6, 2017 by sh!va sh!va comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote if P then Q P is given so we can infer Q Sanjay Sharma answered Aug 11, 2016 Sanjay Sharma comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Ans: B Whenever E is a tautology, P1 AND P2 AND .. Pn -> E is a tautology. Given two premises P1 and P2, we can infer P1 AND P2. If P1 and (P1 -> P2) are given or inferred, then we can infer P2 by the rule of modus ponens (p AND (p->q) -> q). If NOT P2 and (P1 -> P2) are given or inferred, then we can infer NOT P1 by the rule of modens tollens. If P1 and (P1==P2) are given or inferred, we can infer P2. ref: https://www.cs.rochester.edu/~nelson/courses/csc_173/proplogic/reason.html rishu_darkshadow answered Oct 25, 2017 rishu_darkshadow comment Share Follow 0 reply Please log in or register to add a comment.