8 8 votes Consider a clocked sequential circuit as shown in the figure below. Assuming initial state to be Q1 Q0 = 00 For an input sequence X = 1010, the respective output sequence will be _______. Digital Logic + – User007 3.2k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Ashwin_R commented Oct 11, 2016 reply Follow flag 1(LSB)110(MSB).....??? 1 1 replyShare mcjoshi commented Oct 11, 2016 reply Follow flag $1010$ is the answer. 3 3 replyShare Please log in or register to add a comment.
1 1 vote It is coming 1010(from X=0(LSB) to 1(MSB)) KISHALAY DAS answered Oct 11, 2016 KISHALAY DAS comment Share Follow See all 2 Comments 2 2 Comments reply User007 commented Oct 20, 2016 reply Follow flag Can you take a picture of your solution and then attach it in your comment. 0 0 replyShare Rahul Jain25 commented Dec 8, 2016 reply Follow flag I am getting same answer but in key 1001 is given. 0 0 replyShare Please log in or register to add a comment.
0 0 votes Output is Y = (MSB) 0011 (LSB) vamsi2376 answered Nov 8, 2016 vamsi2376 comment Share Follow See 1 comment 1 1 comment reply abhi97.dutta commented Jul 15, 2021 reply Follow flag Instead of Q0(New)XORQ1(New) only Q0(New) will come in the second last line. 0 0 replyShare Please log in or register to add a comment.
0 0 votes I am also getting 1010 as the answer himanshu19 answered Oct 11, 2017 himanshu19 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Answer is 1011 D1 D0 Q1 Q0 Output Y Q1 XOR X Q0 XOR Q1 0 0 X'Q1'+Q0' when x=0, 0 xor 0 = 0 0 xor 0 = 0 0 0 1 when x=1, 0 xor 1 = 1 0 xor 0 = 0 1 0 0 when x=0, 1 xor 0 = 1 0 xor 1 = 1 1 1 1 when x=1, 1 xor 1 = 0 1 xor 1 = 0 0 0 1 ♥_Less answered Dec 14, 2017 ♥_Less comment Share Follow See all 2 Comments 2 2 Comments reply Anu007 commented Dec 14, 2017 reply Follow flag no answer must be (- - 10)i.e. end with 10 1 1 replyShare ♥_Less commented Dec 15, 2017 reply Follow flag I dont think i did anything wrong in the solution. 0 0 replyShare Please log in or register to add a comment.