proving DFA stuck
This DFA fulfills: Define a function diff:{0,1}∗→Zdiff:{0,1}∗→Z, for w∈{0,1}∗w∈{0,1}∗, diff(w)=(diff(w)=(# of 1's in w)−(w)−(# of 0's in ww). Thus, diff(ϵ)=0diff(ϵ)=0; diff(0)=−1diff(0)=−1; diff(1)=1diff(1)=1. Let L={w∈{0,1}∗∣diff(w)=3m for ... the second option: ∀w∈{0,1}∗∀w∈{0,1}∗: a) if δ(q0,w)=q1δ(q0,w)=q1, then w∈L and w=0, for any a∈Z+a∈Z+. What would be the correct option?
This DFA fulfills: Define a function diff:{0,1}∗→Zdiff:{0,1}∗→Z, for w∈{0,1}∗w∈{0,1}∗, diff(w)=(diff(w)=(# of 1's in w)−(w)−(# of 0's in ww). Thus, diff(ϵ)=0diff(ϵ)=0; diff(0)=−1diff(0)=−1; diff(1)=1diff(1)=1. Let L={w∈{0,1}∗∣diff(w)=3m for some m∈Z}L={w∈ ... +. the second option: ∀w∈{0,1}∗∀w∈{0,1}∗: a) if δ(q0,w)=q1δ(q0,w)=q1, then w∈L and w=0, for any a∈Z+a∈Z+. What would be the correct option?
asked
Apr 4, 2019
in Other Colleges
iara84
91 views
