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Syllabus: Random variables, Uniform, Normal, Exponential, Poisson and Binomial distributions. Mean, median, mode and standard deviation. Conditional probability and Bayes theorem

$$\scriptsize{\overset{{\large{\textbf{Mark Distribution in Previous GATE}}}}{\begin{array}{|c|c|c|c|c|c|c|c|}\hline
\textbf{Year}& \textbf{2024-1} &\textbf{2024-2} &\textbf{2023} &\textbf{2022} & \textbf{2021-1}&\textbf{2021-2}&\textbf{Minimum}&\textbf{Average}&\textbf{Maximum}
\\\hline\textbf{1 Mark Count} &2&1&0& 0 &1&1&0&0.83&2
\\\hline\textbf{2 Marks Count} & 1&1&1&0 &2&2&0&1.16&2
\\\hline\textbf{Total Marks} & 4&3&2&0 &5&5&\bf{0}&\bf{3.16}&\bf{5}\\\hline
\end{array}}}$$

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262
Probability
From a deck of 52 cards, what is the probability of picking 2 kings: a)With replacement B)Without replacement Please explain in details. I am new to probability. Thank you. :)
From a deck of 52 cards, what is the probability of picking 2 kings:a)With replacementB)Without replacement Please explain in details. I am new to probability. Thank you....
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265
Conditional Probability
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4 votes
1 answer
267
X and Y are two independent random variables
X and Y are two independent random variables with variances 1 and 2 respectively. Let Z=X-Y. The variance of Z is _____.
X and Y are two independent random variables with variances 1 and 2 respectively. Let Z=X-Y. The variance of Z is _____.
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268
Probablity
Suppose each of three men at a party throws his hat into the center of the room. The hats are first mixed up and each man randomly selects a hat. what is the probability that- a. All of three men select his own hat. b.None of three men select his own hats.
Suppose each of three men at a party throws his hat into the center of the room. The hats are first mixed up and each man randomly selects a hat. what is the probability...
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270
probability
Consider a hash table with 10 slots. Collisions are resolved using linear probing. The probability that if first 3 slots are unfilled and 4th insertions leads to a collisions ________. (Upto 3 decimal places) // my answer is 7/10 * 6/10 * 5/10 * 3/7 = 90/1000 = 0.09
Consider a hash table with 10 slots. Collisions are resolved using linear probing. The probability that if first 3 slots are unfilled and 4th insertions leads to a collis...
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271
Self doubt
1) P(A/B) = P(A $\cap$ B) / P(B) 2) P(A/B) = P(B $\cap$ A) / P(B) What is the difference in this equation.. P(A $\cap$ B) and P(B $\cap$​​​​​​​ A) are same ???
1) P(A/B) = P(A $\cap$ B) / P(B)2) P(A/B) = P(B $\cap$ A) / P(B)What is the difference in this equation..P(A $\cap$ B) and P(B $\cap$​​​​​​​ A) are same ??...
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272
ME Test Series
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274
#MADE ESAY
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275
#made easy test
A pair of dice rolled together till a sum of either 5 or 7 obtained. find probability that 5 comes before 7.
A pair of dice rolled together till a sum of either 5 or 7 obtained. find probability that 5 comes before 7.
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276
Continous Probability
Find the value of $\lambda$ such that function f(x) is valid probability density function $f(x)=\lambda (x-1)(2-x)$ for $1 \leq x \leq 2$ $=0$ otherwise My $\lambda$ is coming to be $- \frac{6}{5}$ Am I correct?
Find the value of $\lambda$ such that function f(x) is valid probability density function$f(x)=\lambda (x-1)(2-x)$ for $1 \leq x \leq 2$$=0$ otherwise My $\lambda$ is com...
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279
SELF DOUBT
TIFR2011-A-6 IN THIS QUESTION WE GET ANSWER 6 BY THIS METHOD . SIMPLE AND STRAIGHT OKK WHEN I APPLY THIS METHOD HERE Expectated no of coin toss THEN I GET X= 1/2 (X +1 ) + 1/4 (X+2 ) (HH CASE) + 1/2 (4 ) Which makes X=6 but answer is 4 .where am i wrong
TIFR2011-A-6 IN THIS QUESTION WE GET ANSWER 6 BY THIS METHOD . SIMPLE AND STRAIGHTOKK WHEN I APPLY THIS METHOD HERE Expectated no of coin toss THEN I GET X= 1/2 (X +1 ) ...
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