24 votes 24 votes Consider a multiplexer with $X$ and $Y$ as data inputs and $Z$ the as the control input. $Z=0$ selects input $X$, and $Z=1$ selects input $Y$. What are the connections required to realize the 2-variable Boolean function $f=T+R$, without using any additional hardware? $\text{R to X, 1 to Y, T to Z}$ $\text{T to X, R to Y, T to Z}$ $\text{T to X, R to Y, 0 to Z}$ $\text{R to X, 0 to Y, T to Z}$ Digital Logic gatecse-2004 digital-logic normal multiplexer + – Kathleen asked Sep 18, 2014 • edited Jun 19, 2018 by Pooja Khatri Kathleen 7.1k views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments raja11sep commented Sep 13, 2022 reply Follow Share Method 1: Z=R, Y=1, X=T Method 2: Z=T, Y=1, X=R 1 votes 1 votes Shreed commented Oct 14, 2023 reply Follow Share Compact truth table T f 0 R 1 1 f = T'R + T =T+R 0 votes 0 votes ꧁༒☬ĿọŗԀ 🆂🅷🅸🆅🅰☬༒꧂ commented Nov 3, 2023 reply Follow Share @Syedarshadali for c it will be grounded and will not active Y so will give o/p R only 1 votes 1 votes Please log in or register to add a comment.
Best answer 32 votes 32 votes Answer is option A. $Z'X + ZY$ Put $Z = T, X = R, Y = 1 $ in $Z'X + ZY$ $= T'R + 1*T$ $= (T+T') (T+R)$ $= T + R$ Digvijay Pandey answered May 15, 2015 • edited Jun 26, 2018 by Digvijay Pandey Digvijay Pandey comment Share Follow See all 2 Comments See all 2 2 Comments reply air1ankit commented Jan 2, 2018 reply Follow Share sir can u please make diagram(mux) for this question.. 0 votes 0 votes jatin khachane 1 commented Nov 6, 2018 reply Follow Share @Digvijay+Pandey Should we consider f = T + R as SOP or POS ?? 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes $f = \overline{Z}.X+{Z}.Y$ We have to make $f = T+R$ Let's try Option A. $f=\overline{T}.R+{T}.1$ => $f=\overline{T}.R+{T}$ => $T+R$ Matched! JashanArora answered Jan 1, 2020 JashanArora comment Share Follow See all 0 reply Please log in or register to add a comment.