12 12 votes How many $128\times 8$ bit RAMs are required to design $32\;\text{K}\times 32$ bit RAM? $512$ $1024$ $128$ $32$ CO & Architecture isro2017 co-and-architecture memory-interfacing + – sh!va 8.5k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 16 16 votes Number of RAM = (32 * K * 32) / 128 * 8 = 25 * 210 * 25 / 27 * 23 =220 / 210 = 1024 option B... akash.dinkar12 answered May 7, 2017 • edited Mar 26, 2018 by akash.dinkar12 akash.dinkar12 comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote Number of $\text{RAMs}$ required $= \frac{32K \times 32}{128\times 8} = \frac{2^{20}}{2^{10}} = 2^{10} = 1024$ Rishi yadav answered May 26, 2017 • edited Apr 20, 2019 by Rishi yadav Rishi yadav comment Share Follow 0 reply Please log in or register to add a comment.
