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A traffic office imposes on an average 5 number of penalities daily on traffic violators.Assume that the number of the penalties on different days is independent and follows a Poisson distribution.The  probability that there will be less than 4 penalties in a day is _______________  ?

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$P(X < 4) = e^{-5}*\sum_{i=0}^{3}\frac{\Lambda^{i}}{i!}$

Solving you get $0.265$
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Given that λ=5λ=5

Let X = number of penalties per day

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