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2 2 votes
The solution to the quadratic equation

x^2-11x+22=0 are x=3 and x=6. What is the base of the numbers?

2 Answers

Best answer
4 4 votes

Root of the equation $x^{2}$ - 11x + 22 = 0 are given as 3 and 6.

Let the base of the number be n.

We can get the base of the number easily by two approaches as follows.

1. Sum of the root = -b / a.
     Where b and a are the coefficients of the general quadratic equation a$x^{2}$ + bx + c = 0.

Therefore $(3)_{n}$ + $(6)_{n}$ = $(11)_{n}$

$\Rightarrow$ 9 = n + 1

$\Rightarrow$ n = 8.

2. Product of the root = c / a.

So, $(3)_{n}$ $(6)_{n}$ = $(22)_{n}$

$\Rightarrow$ 18 = 2n + 2

$\Rightarrow$ n = 8.

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1 1 vote

Suppose the base is a and we have roots 3,6 so let us suppose that it is in base 10 then the equation would be :

{(x-3)(x-6)}10  = {x2+11x+22}a

{x2 - 9x+18}10 = {x2+11x+22}a

equating 9 base 10=11 base a

thus a+1=9


a=8 

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