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In a room containing $28$ people, there are $18$ people who speak English, $15$, people who speak Hindi and $22$ people who speak Kannada. $9$ persons speak both English and Hindi, $11$ persons speak both Hindi and Kannada whereas $13$ persons speak both Kannada and English. How many speak all three languages?

1. $9$
2. $8$
3. $7$
4. $6$

edited | 1.8k views
0
the should mention that all the people know speaking some language else we can not assume the sample space
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yes

Apply set formula of $A$ union $B$ union $C$
$28 = (18 + 15 + 22) - (9 + 11 + 13) + x$
$28 = 55 - 33 + x$
$x = 6$

Correct Answer: $D$

edited
+5

point is that it is not mentioned anywhere that all 28 people must speak atleast one of three language.

hence answer could be either 0 ,1 ,2 ,3 ,4 ,5 ,6 , but as in option only 6 is given , hence answer is 6

+20

mehul vaidya

u are absolutely correct. Since the question is not giving any information about the people who don't speak any of the languages, we should not neglect it.

$| E | = 18, | H | =15 , |K| =22 , |E∩ H| =9 , |E∩K| = 11 , |H∩K|, |E∩H∩K| =X$

Let the people who don't speak any of the languages is Y;

According to the principle of Mutual Exclusion:

$|E∪ H∪ K| = 18 + 15+ 22 -(9+11+13) + X$

$28 - Y = 22 + X$

$X + Y = 6 ----------(1)$

There are $7$ possible pairs of values which satisfy this equation here;

$(6,0),(5,1)(4,2)(3,3)$

Since we have to follow the options, we will take pair$(6,0)$ indicates $X =6$ otherwise $X$ can be $5, 4,3,2,1,0$

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@mehul vaidya

did not get you bro

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@mehul vaidyadid not get you bro Using Venn diagram

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nice explanation
+1 vote

In question given that,

n(EUHUK) =28 ,n(E∩H) =9 ,n(E∩K) =11 ,n(H∩K) =13 ,n(E)=18 ,n(H)=15 , n(K)=22

n(EUHUK) =  n(E) + n(H)+ n(K) - [ n(E∩H) + n(E∩K) + n(H∩K) ] + n(E∩H∩k)

28 = 18 +15 +22 -[9+11+13] + n(E∩H∩k)

n(E∩H∩k) = 6