reopened by
2,416 views
1 votes
1 votes

Which of the following set of components is sufficient to implement any arbitrary Boolean function?

  1. $XOR$ gates, $NOT$ gates
  2. $AND$ gates, $XOR$ gates and $1$
  3. $2$ to $1$ multiplexer
  4. Three input gates that output $(A.B)+C$ for the inputs $A, B, C$
reopened by

1 Answer

1 votes
1 votes
  • a⊕1=  a'
  • a'  ⊕1=a
  • Thus XOR ⊕ and  1 can make NOT gate
  • AND is given

{AND, NOT} is functionally complete.

Answer is B

Answer:

Related questions

7 votes
7 votes
3 answers
1
makhdoom ghaya asked Apr 26, 2016
4,425 views
Any set of Boolean operators that is sufficient to represent all Boolean expressions is said to be complete. Which of the following is not complete ?{$NOT$, $OR$}{$NOR$}{...
4 votes
4 votes
2 answers
2
gatecse asked Dec 17, 2017
2,662 views
In $\text{IEEE}$ floating point representation, the hexadecimal number $\text{0xC0000000}$ corresponds to$-3.0$$-1.0$$-4.0$$-2.0$
0 votes
0 votes
1 answer
3
2 votes
2 votes
3 answers
4
gatecse asked Dec 17, 2017
7,009 views
A $32$-$bit$ adder is formed by cascading $4$-$bit$ CLA adder.The gate delays (latency)for getting the sum bits is$16$$18$$17$$19$