1 1 vote Mathematical Logic + – ankit_thawal 504 views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Ashwin Kulkarni commented Jan 29, 2018 reply Follow flag Its a tautology. try for T->F it will never give that . 1 1 replyShare Mk Utkarsh commented Jan 29, 2018 reply Follow flag I agree with Ashwin For making conclusion false S and T should be false and to make Premises True we already know S should be false hence there arises this situation ($P \wedge (P\rightarrow Q)$) we need Q true here $(S \wedge R)$ S is false hence R should be True ($R \rightarrow \sim Q)$ we need Q false here Q needs to be True and also False that's not possible hence impossible to create True $\rightarrow $ False Hence Tautology 1 1 replyShare Please log in or register to add a comment.