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Test series

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$\int_{0}^{2\pi } ( \sqrt{1 - sin 2x }) dx$

= $\int_{0}^{2\pi } ( \sqrt{sin^{2}x + cos^{2}x - 2sinxcosx }) dx$

=$\int_{0}^{2\pi } | sin x - cos x | dx$

after this how to break into interval  please help

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