Combinational circuits

Question

Comments

Is it D?

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i am getting ( log₂2ⁿ ) - 1 = n-1

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How Shaik?

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with 3 ( n ) variables ===> 8 ( 2ⁿ ) inputs ===> EX-OR between THREE ( n ) variables ===> n variables have only n-1 ex-or's only.

i mean A ⊕ B ⊕ C ===> 2 ex-or gates only

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Formula is wrong.  If n=1 according to you for 3inputs  there are 8(2)=16 inputs are there. This wrong. For 3 input there are 8 inputs (0 to 7)

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@Kiran 568275148 brother,

3 ( n ) variables

it is not 3 multiply by n, it convey let n=3

 

8 ( 2ⁿ ) inputs

is not 8 multiply by 2ⁿ.

it convey... 8 means 2ⁿ. due to i take n=3

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@Shaik sir , $2^n \ inputs$ means $2^n$ minterms and $n$ variables ?

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@Soumya29 mam

2ⁿ inputs means 2^n-1 min terms and 2^n-1 max terms

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@Shaik: then it should be n-1 XORs needed ??

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@Abbas

yes it should be n-1 Ex-oR's, i mistakenly ( you can get that from my second comment ) wrote that formula... i will update it

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Thanks @Shaik

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Thanks to you BRO... you identified where i mistake.

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Yes... If possible number of inputs are $2^n$ then we have n variables and n-1 EXOR gates are needed.

@Shaik sir.  Shouldn't it be $2^n$ inputs means $2^n$ minterms are possible out of which odd parity function will be 1 for $2^{n-1}$ minterms ?

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odd parity function will be 1 for 2ⁿ⁻¹ min terms ?

yes mam